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Create Method (XYZ, XYZ, XYZ)

Creates a new geometric arc object based on three points.

Namespace: Autodesk.Revit.DB
Assembly: RevitAPI (in RevitAPI.dll) Version: 2015.0.0.0 (2015.0.0.0)
Since: 2014

Syntax

C# 
public static Arc Create(
	XYZ end0,
	XYZ end1,
	XYZ pointOnArc
)
Visual Basic 
Public Shared Function Create ( _
	end0 As XYZ, _
	end1 As XYZ, _
	pointOnArc As XYZ _
) As Arc
Visual C++ 
public:
static Arc^ Create(
	XYZ^ end0, 
	XYZ^ end1, 
	XYZ^ pointOnArc
)

Parameters

end0
Type: Autodesk.Revit.DB XYZ
The start point of the arc.
end1
Type: Autodesk.Revit.DB XYZ
The end point of the arc.
pointOnArc
Type: Autodesk.Revit.DB XYZ
A point on the arc.

Return Value

The new arc.

Examples

Copy C# 
// Create a new arc using two ends and a point on the curve
XYZ end0 = new XYZ(1, 0, 0);    // start point of the arc
XYZ end1 = new XYZ(10, 10, 10); // end point of the arc
XYZ pointOnCurve = new XYZ(10, 0, 0);   // point along arc

Arc arc = Arc.Create(end0, end1, pointOnCurve);
Copy VB.NET 
' Create a new arc using two ends and a point on the curve
Dim end0 As New XYZ(1, 0, 0)
' start point of the arc
Dim end1 As New XYZ(10, 10, 10)
' end point of the arc
Dim pointOnCurve As New XYZ(10, 0, 0)
' point along arc
Dim arc__1 As Arc = Arc.Create(end0, end1, pointOnCurve)

Exceptions

Exception Condition
Autodesk.Revit.Exceptions ArgumentNullException A non-optional argument was NULL
Autodesk.Revit.Exceptions ArgumentsInconsistentException The vectors end0 and end1 are coincident. -or- The vectors end0 and pointOnArc are coincident. -or- The vectors end1 and pointOnArc are coincident. -or- Cannot create an arc. -or- Curve length is too small for Revit's tolerance (as identified by Application.ShortCurveTolerance).

See Also